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不用BigDECimAl的小数加法

0.9+0.1=1-0.8= 4.5-4=5.6+4=5.7+3.3=10-4.4=6+6.6= 9.5-2.7=1-0.55=3.7+4.8=7+3.3=0.9+1= 2.7+3.9= 1-0.44=0.7+0.9= 3.25+0.75=14.6-0.4=10-0.1= 14+0.78= 1-0.3=5-0.08=1.1-1= 1 .64+2.35=8.34-6.22= 12.6+3.4=1.3+4.37.2+6.99.3-8.84.4+15.

1.2+1.5=2.7 1.3+1.5=2.8 0.2+1.2=1.4 1.3+1.08=2.38 5.5+2.1=7.6 7.8+1.9=9.7 1.02+1.03=2.05 1.2+1.5=2.7 1.5+1.7=3.2 1.3+1.5=2.8 0.2+1.2=1.4 1.3+1.08=2.38 5.5+2.1=7.6 7.8+1.9=9.7 1.02+1.03=2.05 1.2+1.5=2.7 1.3+1.5=2.8 0.2+1.2=1.4 1.3+1.08=2.38 5.5+2.1=7.6 7.8+1.9=9.7 1.02+1.03=2.05 7.1+7.1=14.2 2.03+2.03=4.06

12.9+12.4= 89.5-55.5=2.3+2.7= 76.1-1.2=8.9+5.7= 1.2-0.1=55.5+44.4= 59.1-32.8=32.4+32.4= 62.7-12.9=54.6+12.3= 99.9-88.8=58.7+69.8= 8.1-1.1=32.1+65.4= 9.1-2.9=74.1+96.3= 10.3-10.1=11.1+22.2= 100.125-94.5125=

double类型保留小数有两种情况:1 在输出时保留两位小数:用printf通过格式字符即可控制小数的保留.如 double a = 1.234; printf(".2lf",a); 会输出1.232 在运行过程中结果保留两位小数.可以借助转为整型,及乘除运算实现.如 double a = 1.235; a = ((int)(a*100+0.5))/100.0; 运算结果,a=1.24.

1、两个小数相加或相减,可以把他们的整数位与小数位拆开,分别进行计算例 10.4+3.1=10+0.4+3+0.1,13.5-10.4=13+0.5-10-0.42、当两个小数被拆开时,可以先把整数位相加,再把小数位相加例 10.4+3.1=10+0.4+3+0.1=13+0.4+0.1,13.5-10.4=13+0.5-10-0.4=3+0.5-0.43、小数位相加时,则与整数位相加相同,对应位相加,逢十进一.例 0.4+0.1=0.5,0.6+0.5=(注意由于6+5=11>10,则需向前进位)1.1,0.4-0.5=(注意由于4-5=-1 评论0 0 0

小数加减法就是把两个小数合并成一个小数运算.用竖式做小数加减法时,只要把小数对齐就行.计算中,得数小数分末尾有“0”可去掉.

1.59+3.95=6.54+0.58=54.49-22.5=23.5+21.35=9.36+43.56=16.65+18.87=0.99+24.85=9.45-6.61=85.69-48.58=45.46-26.57=64.19-29.57=33.84+16.5=3.85+61.18=35.65-19.9=6.49-4.81=35.4-24.58=52.65+9.25=21.65+4.05=26.65-15.24=56.56-

1+1= 2+2= 100+789456612307851693201258601025895451+4547148754+3464=

十以内的小数加减法竖式 给你举例子:1.21 + 4.95 = 6.16 竖式见图:

原式=1-0.98+0.99-0.97+0.96-0.94+0.95-0.93++0.04-0.02+0.03-0.01=(1-0.98+0.99-0.97)+(0.96-0.94+0.95-0.93)++(0.04-0.02+0.03-0.01)=0.2+0.2+0.2++0.2=0.2x25=5

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